tính S=1+1/3+1/5+...+1/(2n-1)

#include <stdio.h>
#include <conio.h>
int main()
{
float n;
float s1=0;
printf("\n nhap vao so n: "); scanf("%f",&n);
for(float i=1;i<=2*n-1;i=i+2)
s1=s1+(1/i);
printf("\n %.3f",s1);
getch();
return 0;
}